The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

  1. 0.138 H
  2. 138.88 H
  3. 13.89 H
  4. 1.389 H

Answer (Detailed Solution Below)

Option 3 : 13.89 H
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Detailed Solution

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Concept:

In most electronic circuits inductor is used to save magnetic energy when electricity is passed through it. Therefore, Inductors are used as energy storage devices.

Energy stored in inductor when current I flows through it is

\(U = \frac{1}{2}L{I^2}\)

where L is the inductance of the inductor.

Calculation:

Given:

Magnetic potential energy, U = 25mJ

Current in the inductor = 60 mA

Energy stored in inductor

\(U = \frac{1}{2}L{I^2}\)

25 × 10-3 = \(\frac{1}{2}\) × L × (60 × 10-3)2 

\(L = \frac{{25 \times 2 \times {{10}^6} \times {{10}^{ - 3}}}}{{3600}}\)

\( = \frac{{500}}{{36}}\)

= 13.89 H

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