If the radius of a sphere is increased by 125%, then by what percentage will its surface area increase (correct to two decimal places)?

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SSC CPO 2024 Official Paper-I (Held On: 28 Jun, 2024 Shift 2)
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  1. 509.54%
  2. 409.76%
  3. 406.25%
  4. 506.25%

Answer (Detailed Solution Below)

Option 3 : 406.25%
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Detailed Solution

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Given:

Initial radius of the sphere = r

Increased radius of the sphere = r + 125% of r

Increased radius of the sphere = r + 1.25r = 2.25r

Formula Used:

Surface area of a sphere = 4πr2

Calculation:

Initial surface area = 4πr2

New surface area with increased radius = 4π(2.25r)2

⇒ New surface area = 4π(5.0625r2)

⇒ New surface area = 20.25πr2

Increase in surface area = New surface area - Initial surface area

⇒ Increase in surface area = 20.25πr2 - 4πr2

⇒ Increase in surface area = 16.25πr2

Percentage increase in surface area = (Increase in surface area / Initial surface area) × 100

⇒ Percentage increase in surface area = (16.25πr2 / 4πr2) × 100

⇒ Percentage increase in surface area = (16.25 / 4) × 100

⇒ Percentage increase in surface area = 4.0625 × 100

⇒ Percentage increase in surface area = 406.25%

The percentage increase in surface area is 406.25%.

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