A thief running at 7 km/h is chased by a policeman whose speed is 12 km/h. If the thief is 280 m ahead of the policeman, then the time required for the policeman to catch the thief will be:

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SSC CPO 2024 Official Paper-I (Held On: 27 Jun, 2024 Shift 1)
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  1. \(3 \frac{1}{25}\) minutes 
  2. \(3 \frac{9}{25}\) minutes
  3. \(4 \frac{9}{25}\) minutes
  4. \(3 \frac{2}{25}\) minutes

Answer (Detailed Solution Below)

Option 2 : \(3 \frac{9}{25}\) minutes
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SSC CPO : English Comprehension Sectional Test 1
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Detailed Solution

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Given:

Speed of the thief = 7 km/h

Speed of the policeman = 12 km/h

Distance between the thief and the policeman = 280 m

Concept:

Relative speed is the difference in speeds when two objects move in the same direction.

Formula used:

Time = Distance / Relative Speed

Calculation:

Convert distance into km:

⇒ 280 m = 280/1000 km = 0.28 km

Calculate relative speed:

⇒ Relative Speed = 12 km/h - 7 km/h = 5 km/h

Calculate time required to catch the thief:

⇒ Time = Distance / Relative Speed

⇒ Time = 0.28 km / 5 km/h

⇒ Time = 0.056 hours

Convert time into minutes:

⇒ Time = 0.056 × 60 minutes

⇒ Time = 3.36 minutes

Convert decimal minutes into fraction:

⇒ Time = 3 (9/25) minutes

∴ The time required for the policeman to catch the thief is 3 (9/25) minutes.

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