Question
Download Solution PDFनीचे दी गई तालिका में पांच कंपनियों की बाइक्स और कारों की बिक्री को दर्शाया गया है।
| कंपनियों | बाइक | कार |
| पी | 200 | 1200 |
| क्यू | 100 | 300 |
| आर | 500 | 700 |
| एस | 600 | 1000 |
| टी | 800 | 800 |
J1 = कंपनी P, Q और R की बाइक्स की औसत बिक्री।
J2 = कंपनी R, S और T की कारों की औसत बिक्री।
(J1 ∶ J2) का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया:
| कंपनियों | बाइक | कार |
| P | 200 | 1200 |
| Q | 100 | 300 |
| R | 500 | 700 |
| S | 600 | 1000 |
| T | 800 |
800 |
प्रयुक्त अवधारणा:
औसत = \( {\sum x_i\over n}\)
जहाँ n संस्थाओं की संख्या है।
गणना:
J 1 = \({sales \ of \ bikes \ by(P+Q+R)\over3 }\)
जे 1 = \({200+100+500\over3 }\)
जे 1 = \({800\over3}\)
अब, J 2 = \({sales \ of \ cars \ by(S+R+T)\over3 }\)
J2 = \({1000+700+800\over3}\)
J2 = \({2500\over3}\)
J 1 : J 2 = \({800\over3}\) : \(2500\over3\)
⇒ 8 : 25
∴ J 1 :J 2 का मान '8 : 25' है।
Last updated on Jul 9, 2025
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