Question
Download Solution PDFConsider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at x = 0.1 cm when the jaws of Vernier callipers are closed.
If the main scale reading for the diameter is M = 5 cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Least count = 1 MSD − 1 VSD
1 MSD − (9 / 10) MSD
= (1 / 10) MSD
= (1 / 10) × 0.1 cm = 0.01 cm
Zero error = +0.1 cm
Main scale reading = 5 cm
Vernier scale reading = 8 × 0.01 = 0.08 cm
Final measurement of diameter
= 5 + 0.08 − 0.1 = 4.98 cm
Correct option is: (3) 4.98 cm
Last updated on Jun 16, 2025
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