Question
Download Solution PDFTwo coils having self-inductance of 30 H and 40 H are connected in series opposing connection. Find total inductance of the series connection, if the mutual inductance between the coils is 0.5 H.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The equivalent inductance when connected in:
Case 1: Series addition
\(L_{eq}=L_1+L_2+2M\)
Case 2: Series opposition
\(L_{eq}=L_1+L_2-2M\)
where, L1 and L2 are self inductances
M is mutual inductance
Calculation
Given, L1 = 30 H and L2 = 40 H
M = 0.5 H
\(L_{eq}=(30+40)-(2\times 0.5)\)
Leq = 69 H
Additional Information For a parallel circuit
The total inductance for parallel connection is given by:
\(L_{eq}={L_1L_2\space -\space M^2\over L_1\space + \space L_2 \space \mp \space 2M}\)
- sign is used for parallel addition
+ sign is used for parallel opposition
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