Question
Download Solution PDFThe specific volume of air is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Specific Volume:
\(v = \frac{V}{m} \)
For the air, we can use ideal gas equation
PV = mRT
⇒ V/m = RT/P
Calculation:
Given: For air, m = 1kg, R = 287 J/kg.K, T = 300 K, P = 101.325 kPa
Specific Volume:
⇒ V/m = (287 × 300)/101325 m3/kg
⇒ V/m ≈ 0.82 m3/kg
∵ 1 = 1000 L
⇒ V/m ≈ 0.82 × 1000 ≈ 820 L/kg
∵ 1 mL = 1 cm3
⇒ V/m = 0.820 mL/kg
⇒ V/m ≈ 0.820 cm3/kg
- The specific volume of air is 820 L/kg.
So, the correct option it (3).
Last updated on Jul 1, 2025
-> SSC JE ME Notification 2025 has been released on June 30.
-> The SSC JE Mechanical engineering application form are activated from June 30 to July 21.
-> SSC JE 2025 CBT 1 exam for Mechanical Engineering will be conducted from October 2 to 31.
-> SSC JE exam to recruit Junior Engineers in different disciplines under various departments of the Central Government.
-> The selection process of the candidates for the SSC Junior Engineer post consists of Paper I, Paper II, Document Verification, and Medical Examination.
-> Candidates who will get selected will get a salary range between Rs. 35,400/- to Rs. 1,12,400/-.
-> Candidates must refer to the SSC JE Previous Year Papers and SSC JE Civil Mock Test, SSC JE Electrical Mock Test, and SSC JE Mechanical Mock Test to understand the type of questions coming in the examination.