Question
Download Solution PDF9 + 9 2 + ..+ 9 (2n+1) यांना 6 ने विभाजित केल्यावर बाकी किती असेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिल्याप्रमाणे:
9 + 9 2 +..+ 9 (2n+1)
वापरलेली संकल्पना:
3 च्या कोणत्याही विषम गुणकाला 6 ने विभाजित केल्यास बाकी 3 राहील.
गणना:
3 च्या कोणत्याही विषम गुणकाला 6 ने विभाजित केल्यास बाकी 3 राहील.
9 हा 3 चा विषम गुणक आहे. आणि 9 चे सर्व घात 3 चे विषम गुणक आहेत.
म्हणून, जेव्हा वर सूचीबद्ध केलेल्या 9 च्या 8 घातांपैकी प्रत्येकाला 6 ने विभाजित केले जाते, तेव्हा प्रत्येकात बाकी 3 राहील.
उत्तर 3 आहे.
Last updated on Jul 22, 2025
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