9 + 9 2 + ..+ 9 (2n+1) यांना 6 ने विभाजित केल्यावर बाकी किती असेल?

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SSC CHSL Exam 2023 Tier-I Official Paper (Held On: 11 Aug, 2023 Shift 4)
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Answer (Detailed Solution Below)

Option 4 : 3
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दिल्याप्रमाणे

9 + 9 2 +..+ 9 (2n+1)

वापरलेली संकल्पना:

3 च्या कोणत्याही विषम गुणकाला 6 ने विभाजित केल्यास बाकी 3 राहील.

गणना:

3 च्या कोणत्याही विषम गुणकाला 6 ने विभाजित केल्यास बाकी 3 राहील.

9 हा 3 चा विषम गुणक आहे. आणि 9 चे सर्व घात 3 चे विषम गुणक आहेत.

म्हणून, जेव्हा वर सूचीबद्ध केलेल्या 9 च्या 8 घातांपैकी प्रत्येकाला 6 ने विभाजित केले जाते, तेव्हा प्रत्येकात बाकी राहील.

उत्तर 3 आहे.

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