Question
Download Solution PDFA आणि B या दोन शहरांमधील अंतर 800 किमी आहे. ट्रेन A ते B पर्यंतचा प्रवास 60 किमी प्रतितास वेगाने पूर्ण करते आणि 40 किमी प्रतितास या एकसमान वेगाने A कडे परत येते. संपूर्ण प्रवासादरम्यान ट्रेनचा सरासरी वेग शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
A आणि B या दोन शहरांमधील अंतर = 800 किमी
A ते B पर्यंत ट्रेनचा वेग = 60 किमी/तास
B ते A पर्यंत ट्रेनचा वेग = 40 किमी/तास
संकल्पना:
येथे, दोन्ही स्थितींमध्ये पार केलेले अंतर समान आहे. म्हणून,
सरासरी वेग = 2V1×V2/(V1 + V2)
सरासरी वेग = एकूण अंतर/एकूण वेळ.
गणना:
V1 = 60 किमी/तास, V2 = 40 किमी/तास
सरासरी वेग = (2 × 60 × 40)/(60 + 40)
सरासरी वेग = 4800/100 = 48
∴ संपूर्ण प्रवासादरम्यान ट्रेनचा सरासरी वेग 48 किमी/तास आहे.
Last updated on Jun 30, 2025
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