30 Ω प्रतिरोध द्वारा उपभुक्त शक्ति है:

F1 Engineering Arbaz 29-12-23 D12

This question was previously asked in
SSC JE Electrical 9 Oct 2023 Shift 3 Official Paper-I
View all SSC JE EE Papers >
  1. 10 W
  2. 300 W
  3. 3000 W
  4. 9000 W

Answer (Detailed Solution Below)

Option 3 : 3000 W
Free
Electrical Machine for All AE/JE EE Exams Mock Test
7.8 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

संकल्पना

किसी भी प्रतिरोध पर शक्ति निम्न के द्वारा दी जाती है?:

\(P={V^2\over R}\)

जहाँ, P = शक्ति

V = आपूर्ति वोल्टेज

R = प्रतिरोध

गणना

समानांतर परिपथ में वोल्टेज समान रहता है। इसलिए, 30Ω प्रतिरोध पर वोल्टेज 300 V है।

30 Ω प्रतिरोध द्वारा उपभुक्त शक्ति इस प्रकार दी गई है:

\(P={300^2\over 30}\)

P = 3000 W

Additional Informationएक श्रेणी परिपथ के लिए, किसी भी प्रतिरोध पर शक्ति दी जाती है:

\(P=I^2\times R\)

Latest SSC JE EE Updates

Last updated on Jul 1, 2025

-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.

-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

More Network Elements Questions

Get Free Access Now
Hot Links: teen patti cash teen patti apk teen patti master golden india teen patti classic teen patti master update