Question
Download Solution PDFक्रमशः आंतरिक और बाहरी त्रिज्याएँ r1 और r2 के सिलेंडर की दीवारों के माध्यम से ऊष्मा ___________ के व्युत्क्रमानुपाती है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
हमारे पास बेलनाकार दीवार के माध्यम से ऊष्मा चालन है,
\(Q=\frac{2\pi kL(\Delta T)}{ln(\frac{r_2}{r_1})}\)
जहाँ, k = तापीय चालकता, L = सिलेंडर की लंबाई
उपरोक्त समीकरण से,
\(Q\propto \frac{1}{ln(\frac{r_2}{r_1})}\)
इसलिए, ऊष्मा चालन \(\ln \left( {\frac{{{r_2}}}{{{r_1}}}} \right) \) के व्युत्क्रमानुपाती होता है।
Last updated on Jun 13, 2025
-> BPSC AE 2025 exam date has been revised. The exam will be conducted on July 17, 18 & 19 now.
-> Candidates who were facing technical issues while filling form can now fill the BPSC AE application form 2025 without any issue.
->BPSC AE age limit 2025 has been revised.
->BPSC AE application form 2025 was released on April 30. The last date to fill BPSC AE form 2025 was May 28.
->BPSC AE interview call letters released for Advt. 32/2024.
->BPSC AE notification 2025 has been released.
->A total of 1024 vacancies are announced through BPSC AE recruitment 2025
->The BPSC Exam Calendar 2025 has been released for the Assistant Engineer Recruitment.
-> The selection will be based on a written exam and evaluation of work experience.
-> Candidates with a graduation in the concerned engineering stream are eligible for this post.
-> To prepare for the exam solve BPSC AE Previous Year Papers. Also, attempt the BPSC AE Civil Mock Tests.