Who among the following scored the maximum overall percentage? 

Name	Marks (out of 100)
	English	Hindi	Maths	Science	IT
Simran	78	65	89	78	66
Sanjana	87	70	95	84	84
Payal	93	73	65	77	85
Bhumika	74	84	88	87	79
Neha	82	87	84	85	89
Jyoti	69	90	93	88	92

Given:

Name and their respective marks in five subjects:

Simran: English 78, Hindi 65, Maths 89, Science 78, IT 66

Sanjana: English 87, Hindi 70, Maths 95, Science 84, IT 84

Payal: English 93, Hindi 73, Maths 65, Science 77, IT 85

Bhumika: English 74, Hindi 84, Maths 88, Science 87, IT 79

Neha: English 82, Hindi 87, Maths 84, Science 85, IT 89

Jyoti: English 69, Hindi 90, Maths 93, Science 88, IT 92

Formula used:

Overall Percentage = \(\dfrac{\text{Sum of Marks in All Subjects}}{\text{Total Marks}} \times\) 100

Calculations:

For Simran:

Sum of Marks = 78 + 65 + 89 + 78 + 66 = 376

Overall Percentage = \(\dfrac{376}{500} \times\) 100 = 75.2 %

For Sanjana:

Sum of Marks = 87 + 70 + 95 + 84 + 84 = 420

Overall Percentage = \(\dfrac{420}{500} \times\) 100 = 84 %

For Payal:

Sum of Marks = 93 + 73 + 65 + 77 + 85 = 393

Overall Percentage = \(\dfrac{393}{500} \times\) 100 = 78.6 %

For Bhumika:

Sum of Marks = 74 + 84 + 88 + 87 + 79 = 412

Overall Percentage = \(\dfrac{412}{500} \times\) 100 = 82.4 %

For Neha:

Sum of Marks = 82 + 87 + 84 + 85 + 89 = 427

Overall Percentage = \(\dfrac{427}{500} \times\) 100 = 85.4 %

For Jyoti:

Sum of Marks = 69 + 90 + 93 + 88 + 92 = 432

Overall Percentage = \(\dfrac{432}{500} \times\) 100 = 86.4 %

∴ The correct answer is option 2 (Jyoti).