While covering a distance of 54 km, a man noticed that after cycling for 1 hour 15 minutes, the distance covered by him was \(\frac{7}{9}\) of the remaining distance. What was his speed (in km/hr)?

Question

Question

This question was previously asked in

RRB NTPC Graduate Level CBT-I Official Paper (Held On: 09 Jun, 2025 Shift 1)

Answer 1

Given:

Total distance = 54 km

Time = 1 hr 15 min = 1.25 hr

Distance covered = \(\frac{7}{9}\) of the remaining distance

Formula used:

Speed = Distance ÷ Time

Calculation:

Let distance covered = x km

Then remaining distance = 54 - x

x = (7/9) × (54 - x)

⇒ 9x = 7(54 - x)

⇒ 9x = 378 - 7x

⇒ 9x + 7x = 378

⇒ 16x = 378

⇒ x = 378 ÷ 16 = 23.625 km

Speed = 23.625 ÷ 1.25 = 18.9 km/hr

∴ The man's speed is 18.9 km/hr.

Download Solution PDF