Which of the following systems has maximum number of unpaired electrons ?

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  1. d6 (Tetrahedral)
  2. d7 (Octahedral, High Spin)
  3. d4 (Octahedral, low spin)
  4. d9 (Octahedral)

Answer (Detailed Solution Below)

Option 1 : d6 (Tetrahedral)
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Detailed Solution

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CONCEPT:

Unpaired Electrons in Different Geometries

  • The number of unpaired electrons in a coordination complex is determined by the electron configuration of the metal ion and the geometry of the complex (tetrahedral or octahedral).
  • In a tetrahedral geometry, the crystal field splitting energy (Δt) is lower than in an octahedral geometry. This results in more unpaired electrons because the energy gap between orbitals is smaller, so electrons do not pair up as easily.
  • In an octahedral geometry, the crystal field splitting energy (Δo) is larger, which can lead to different numbers of unpaired electrons depending on whether the complex is high-spin or low-spin.

EXPLANATION:

  • d6 (Tetrahedral):
    • In a tetrahedral field, the e orbitals (lower energy) are filled first, followed by the t2 orbitals (higher energy).
    • For a d6 configuration in a tetrahedral field, the electrons will occupy the orbitals as follows: 2 electrons will pair up in the e orbitals, and the remaining 4 electrons will singly occupy the t2 orbitals.
    • Number of unpaired electrons: 4 unpaired electrons.
  • d7 (Octahedral, High Spin):
    • In a high-spin octahedral complex, the\( t_{2g}\)orbitals (lower energy) are filled first, followed by the \(e_g\)orbitals (higher energy).
    • For a d7 configuration, the electrons will occupy the orbitals as follows: 3 electrons will singly occupy the \(t_{2g}\)orbitals, and the remaining 4 electrons will occupy the \(e_g\) orbitals, with 2 of them being unpaired.
    • Number of unpaired electrons: 3 unpaired electrons.
  • d4 (Octahedral, Low Spin):
    • In a low-spin octahedral complex, the \(t_{2g}\) orbitals are filled first due to the strong crystal field, which causes the electrons to pair up in the lower energy orbitals before occupying the higher energy \(e_g\) orbitals.
    • For a d4 configuration, all 4 electrons will pair up in the \(t_{2g}\) orbitals.
    • Number of unpaired electrons: 2 unpaired electrons.
  • d9 (Octahedral):
    • In an octahedral field, the \(t_{2g}\) orbitals are filled first, followed by the \(e_g\) orbitals.
    • For a d9 configuration, 6 electrons will pair up in the \(t_{2g}\) orbitals, and 3 electrons will occupy the \(e_g\) orbitals, with 1 unpaired electron in the \(e_g\) orbitals.
    • Number of unpaired electrons: 1 unpaired electron.

CONCLUSION:

The correct answer is d6 (Tetrahedral) with 4 unpaired electrons.

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