Which of the following has highest CFSE ?

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HPSC Assistant Professor 2018 Chemistry (Official Paper)
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  1. (FeCl4)2-
  2. [TiF6l3-
  3. [Cr(H2O)6l3+
  4. [Mn(H2O)6]2+

Answer (Detailed Solution Below)

Option 3 : [Cr(H2O)6l3+
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Detailed Solution

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CONCEPT:

Crystal Field Stabilization Energy (CFSE)

  • CFSE is the energy difference between the energy of a complex in its actual electronic configuration and the energy it would have if the electrons were evenly distributed.
  • CFSE depends on the geometry of the complex (octahedral, tetrahedral, etc.), the oxidation state of the metal, and the nature of the ligands.

EXPLANATION:

  • (FeCl4)2-: Iron is in the +2 oxidation state with a d6 configuration in a tetrahedral field. Tetrahedral complexes generally have lower CFSE, and for d6 configuration, the CFSE is negligible.
  • [TiF6]3-: Titanium is in the +3 oxidation state with a d1 configuration in an octahedral field. The CFSE for d1 is \(-0.4 \Delta_o\), which is moderate.
  • [Cr(H2O)6]3+: Chromium is in the +3 oxidation state with a d3 configuration in an octahedral field. The CFSE for d3 is \(-1.2 \Delta_o\), making it the highest among the options.
  • [Mn(H2O)6]2+: Manganese is in the +2 oxidation state with a d5 configuration in an octahedral field. The CFSE is zero due to symmetric filling of the t2g and eg orbitals.

CONCLUSION:

The correct answer is [Cr(H2O)6]3+.

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