What is entered variable map?

This question was previously asked in
UGC NET Paper 2: Electronic Science 3rd Dec 2021 Shift 2
View all UGC NET Papers >
  1. A map to solve the sequential circuits.
  2. An alternative to Karnaugh Map where the variable is placed as output.
  3. A modified version of Karnaugh Map where the variable is placed as composite.
  4. A tabular method for logic simplification.

Answer (Detailed Solution Below)

Option 2 : An alternative to Karnaugh Map where the variable is placed as output.
Free
UGC NET Paper 1: Held on 21st August 2024 Shift 1
16.1 K Users
50 Questions 100 Marks 60 Mins

Detailed Solution

Download Solution PDF

Variable Entrant Map (VEM)

K-map is the best manual technique to solve Boolean equations, but it becomes difficult to manage when the number of variables exceeds 5 or 6.

So, a technique called Variable Entrant Map (VEM) is used to increase the effective size of the k-map.

It allows a smaller map to handle a large number of variables. This is done by writing output in terms of input.

Example: A 3-variable function can be defined as a function of 2 variables if the output is written in terms of a third variable.

Consider a function F(A,B,C) = (0,1,2,5)

A

B

C

F

0

0

0

1

0

0

1

1

0

1

0

1

0

1

1

0

1

0

0

0

1

0

1

1

1

1

0

0

1

1

1

0

If we define F in terms of ‘C’, then this function can be written as:

A

B

F

0

0

1

0

1

\(\overline {C}\)

1

0

C

1

1

0

Latest UGC NET Updates

Last updated on Jun 27, 2025

-> Check out the UGC NET Answer key 2025 for the exams conducted from 25th June.

-> The UGC Net Admit Card has been released on its official website today.

-> The UGC NET June 2025 exam will be conducted from 25th to 29th June 2025.

-> The UGC-NET exam takes place for 85 subjects, to determine the eligibility for 'Junior Research Fellowship’ and ‘Assistant Professor’ posts, as well as for PhD. admissions.

-> The exam is conducted bi-annually - in June and December cycles.

-> The exam comprises two papers - Paper I and Paper II. Paper I consists of 50 questions and Paper II consists of 100 questions. 

-> The candidates who are preparing for the exam can check the UGC NET Previous Year Papers and UGC NET Test Series to boost their preparations.

Get Free Access Now
Hot Links: teen patti master 51 bonus teen patti mastar teen patti master plus teen patti winner