Two stations T1 and T2 300 km apart. A car starts from station T1 at 8 am and moves towards station T2 at a speed of 45 km/hr. and at 10 am another car starts from station T2 towards T1 at a speed of 60 km/hr. Then the cars will meet at:  

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SSC CHSL Exam 2024 Tier-I Official Paper (Held On: 03 Jul, 2024 Shift 1)
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  1. 1:00 p.m.
  2. 10:00 a.m.
  3. 12:00 p.m. 
  4. 11:00 a.m. 

Answer (Detailed Solution Below)

Option 3 : 12:00 p.m. 
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Detailed Solution

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Given:

Two stations T1 and T2 are 300 km apart. A car starts from station T1 at 8 am towards T2 at 45 km/hr. At 10 am, another car starts from station T2 towards T1 at 60 km/hr.

Concept:

To find the meeting time of two moving objects, we calculate the time when the sum of the distances covered by both objects equals the total distance between them.

Formula Used:

Distance = Speed × Time

Calculation:

1. Calculate the distance covered by the first car by 10 am:

⇒ Distancefirst car = Speed × Time

⇒ Distancefirst car = 45 km/hr × 2 hrs

⇒ Distancefirst car = 90 km

2. Remaining distance to be covered after 10 am:

⇒ Remaining Distance = Total Distance - Distancefirst car

⇒ Remaining Distance = 300 km - 90 km

⇒ Remaining Distance = 210 km

3. Combined speed of both cars:

⇒ Combined Speed = Speedfirst car + Speedsecond car

⇒ Combined Speed = 45 km/hr + 60 km/hr

⇒ Combined Speed = 105 km/hr

4. Time taken to cover the remaining distance:

⇒ Time = Distance / Combined Speed

⇒ Time = 210 km / 105 km/hr

⇒ Time = 2 hrs

5. Time when the cars will meet:

⇒ Meeting Time = 10 am + 2 hrs

⇒ Meeting Time = 12:00 p.m.

∴ The cars will meet at 12:00 p.m.

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