Question
Download Solution PDFTwo stations T1 and T2 300 km apart. A car starts from station T1 at 8 am and moves towards station T2 at a speed of 45 km/hr. and at 10 am another car starts from station T2 towards T1 at a speed of 60 km/hr. Then the cars will meet at:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Two stations T1 and T2 are 300 km apart. A car starts from station T1 at 8 am towards T2 at 45 km/hr. At 10 am, another car starts from station T2 towards T1 at 60 km/hr.
Concept:
To find the meeting time of two moving objects, we calculate the time when the sum of the distances covered by both objects equals the total distance between them.
Formula Used:
Distance = Speed × Time
Calculation:
1. Calculate the distance covered by the first car by 10 am:
⇒ Distancefirst car = Speed × Time
⇒ Distancefirst car = 45 km/hr × 2 hrs
⇒ Distancefirst car = 90 km
2. Remaining distance to be covered after 10 am:
⇒ Remaining Distance = Total Distance - Distancefirst car
⇒ Remaining Distance = 300 km - 90 km
⇒ Remaining Distance = 210 km
3. Combined speed of both cars:
⇒ Combined Speed = Speedfirst car + Speedsecond car
⇒ Combined Speed = 45 km/hr + 60 km/hr
⇒ Combined Speed = 105 km/hr
4. Time taken to cover the remaining distance:
⇒ Time = Distance / Combined Speed
⇒ Time = 210 km / 105 km/hr
⇒ Time = 2 hrs
5. Time when the cars will meet:
⇒ Meeting Time = 10 am + 2 hrs
⇒ Meeting Time = 12:00 p.m.
∴ The cars will meet at 12:00 p.m.
Last updated on Jul 23, 2025
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