The number nearest to 7658 and exactly divisible by 45 is:

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SSC CHSL Exam 2024 Tier-I Official Paper (Held On: 04 Jul, 2024 Shift 1)
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  1. 7650
  2. 7640
  3. 7645
  4. 7660

Answer (Detailed Solution Below)

Option 1 : 7650
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Detailed Solution

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Given:

Number to be checked: 7658

Divisor: 45

Formula Used:

Nearest number divisible by a given number = (Given number / Divisor) × Divisor

Calculation:

First, find the quotient when 7658 is divided by 45:

Quotient = 7658 / 45

⇒ Quotient = 170.1778 (approximately)

Now, multiply the integer part of the quotient by 45:

Nearest lower number divisible by 45 = 170 × 45

⇒ 170 × 45 = 7650

Next, check the next number by adding 1 to the integer part of the quotient and multiplying by 45:

Nearest higher number divisible by 45 = 171 × 45

⇒ 171 × 45 = 7695

Now, compare the differences:

Difference with 7650 = 7658 - 7650 = 8

Difference with 7695 = 7695 - 7658 = 37

Since 8 < 37, the number nearest to 7658 and exactly divisible by 45 is: 7650

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