Question
Download Solution PDFThe following data relate to a single-cylinder reciprocating engine: mass of reciprocating parts = 40 kg, mass of revolving parts = 30 kg at crank radius, speed = 150 rpm, stroke = 350 mm. If 60% of the reciprocating parts and all the revolving parts are to be balanced, what is the balance mass required at a radius of 320 mm ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
mrω2 = Bbω2
mr = Bb
m = mass to be balanced, B = Mass required for balancing the mass.
r and b are the radius of mass to be balanced and mass required for balancing.
Calculation:
Given:
mass of reciprocating parts = 40 kg, mass of revolving parts = 30 kg at crank radius, speed = 150 rpm, stroke = 350 mm
60% of the reciprocating parts and all the revolving parts are to be balanced
b = 320 mm, Stroke = 2r = 350 mm, ∴ r = 175 mm.
Mass to be balanced
m = mrot + 0.60mreci
m = 30 + (0.60)*40 = 54 kg
mr = Bb
54 × 175 = B × 320
B = 29.53 kg
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