Question
Download Solution PDFThe current waveform as shown in the figure is applied in a pure resistor of 10 Ω. What is the power dissipated in the resistor?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPower dissipated in the resistor \(P = I_{rms}^2R\)
The given waveform is a triangular waveform.
\({I_{rms}} = \frac{{{I_m}}}{{\sqrt 3 }} = \frac{9}{{\sqrt 3 }} = 3\sqrt 3 \;A\)
\(P = I_{rms}^2R = {\left( {3\sqrt 3 } \right)^2} \times 10 = 270\;W\)Last updated on Jun 16, 2025
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