Question
Download Solution PDF\(7 b-\frac{1}{4 b}=7\) , అయిన \(16 b^2+\frac{1}{49 b^2}\) విలువ ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFసూత్రం ఉపయోగించబడింది
(a - b) 2 = a 2 + b 2 - 2ab
లెక్కింపు
సమీకరణంను 4/7తో గుణించడం.
⇒ 4/7 × (7b - 1/4b) = 7 × 4/7
⇒ 4b - 1/7b = 4
రెండు వైపులా వర్గం చేయడం:
⇒ (4b - 1/7b)2 = 42
⇒ \(16 b^2+\frac{1}{49 b^2}\)- 2 × 4 × 1/7 = 16
⇒ \(16 b^2+\frac{1}{49 b^2}\) = 16 + 8/7
⇒ \(16 b^2+\frac{1}{49 b^2}\) = 120/7
విలువ 120/7.
Last updated on Jul 22, 2025
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