\(\Delta\)ABC இல், \(\overline {AD}\) என்பது \(\angle\)A இன் இரு சமவெட்டி மற்றும் D என்பது \(\overline {BC}\) இல் ஒரு புள்ளியாகும். m (\(\overline {AC}\)) = 4.2 செ.மீ, m (\(\overline {BD}\)) = 4 செ.மீ மற்றும் m (\(\overline {BC}\)) = 7 செ.மீ எனில், m (\(\overline {AB}\)) ஐக் கண்டறியவும்.

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RRB Group D 6 Oct 2022 Shift 1 Official Paper
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  1. 5.2 செ.மீ
  2. 4.2 செ.மீ
  3. 4.8 செ.மீ
  4. 5.6 செ.மீ

Answer (Detailed Solution Below)

Option 4 : 5.6 செ.மீ
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Detailed Solution

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கொடுக்கப்பட்டவை:

 

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)ABC இல், \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) என்பது \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)A இன் இரு சமவெட்டி மற்றும் D என்பது \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) இல் ஒரு புள்ளியாகும். m (\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)) = 4.2 செ.மீ, m (\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)) = 4 செ.மீ மற்றும் m (\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)) = 7 செ.மீ

கணக்கீடு:

DC = BC - BD = 7 - 4 = 3 செ.மீ

கோண இருமுனை தேற்றத்தின்படி:

AB : AC = BD : DC

⇒ AB : 4.2 = 4 : 3

⇒ AB = 4 × 4.2/3

⇒ AB = 5.6 cm

எனவே, தேவையான மதிப்பு 5.6 செ.மீ.

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