Some marbles are to be packed in four boxes, A, B, C and D, in the proportion of 6 : 3 : 7 : 5. If box B has 400 less marbles than box D, then how many marbles are there in total in all the boxes?

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RRB NTPC Graduate Level CBT-I Official Paper (Held On: 09 Jun, 2025 Shift 1)
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  1. 4100
  2. 4000
  3. 4200
  4. 3900

Answer (Detailed Solution Below)

Option 3 : 4200
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Detailed Solution

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Given:

Marbles are distributed in boxes A, B, C, and D in the ratio 6:3:7:5.

Box B has 400 less marbles than box D.

Formula used:

Let the number of marbles in the boxes be 6x, 3x, 7x, and 5x for A, B, C, and D, respectively.

Calculation:

Marbles in Box B = Marbles in Box D - 400

⇒ 3x = 5x - 400

⇒ 5x - 3x = 400

⇒ x = 200

Now, calculate the total number of marbles:

Total marbles = 6x + 3x + 7x + 5x

Total marbles = 21x

⇒ Total marbles = 21 × 200

⇒ Total marbles = 4200

∴ The correct answer is option (3).

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