Question
Download Solution PDFRavi and Suhas walk at the speed of 2 km/h and 4 km/h respectively from A to B which is 24 km apart. Suhas reaches B, immediately turns back and meets Ravi at C. Find the distance between A to C.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven
Speed of Ravi = 2 km/h
Speed of Suhas = 4 km/h
Distance between A to B = 24 km
Concept:
Relative speed and time taken to meet
Calculation:
⇒ Time taken by Suhas to reach B = 24 km/4 km/h = 6 hours
In that time Ravi covers 2 × 6 = 12km
Now the Remaining distance to cover for Ravi is 24 - 12 = 12 km
Now the relative speed for 12km as Suhas turns back is 4 + 2 = 6 km/hr
The meeting time is 12/6 = 2 hr.
Now in 2 hr Ravi moves = 2 × 2 = 4 km
So the total distance between A and C is 12 + 4 = 16km
Therefore, the distance from A to C is 16 km.
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