Question
Download Solution PDFP1 is 4 times as efficient as P2 and together they complete a work in 16 days. How many days will P1 alone take to complete the same work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:-
P1 = 4 × P2
P1 + P2 = 16 days
Calculation:-
The ratio of efficiency of P1 and P2 = 4 ∶ 1
The ratio of time taken is inversely proportional to the ratio of efficiency
The ratio of time taken by P1 and P2 = 1 ∶ 4
Total work = Efficiency × time taken
= 16 × 5
= 80 units
Time taken by P1 = 80/4 = 20 days
The answer is 20 days.
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