दिलेले समीकरण अचूक करण्यासाठी कोणत्या दोन चिन्हांची अदलाबदल केली पाहिजे?

912 - 456 × 28 + 390 ÷ 2 = 444

This question was previously asked in
SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 1)
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  1. ÷ आणि -
  2. ÷ आणि +
  3. - आणि + 
  4. ÷ आणि × 

Answer (Detailed Solution Below)

Option 1 : ÷ आणि -
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Detailed Solution

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1. ÷ आणि -

912 ÷ 456 × 28 + 390 - 2 = 444

⇒ × 28 + 390 - 2 = 444

⇒ 56 + 390 - 2 = 444

⇒ 446 - 2 = 444

⇒ 444 = 444

2. ÷ आणि +

912 - 456 × 28 ÷ 390 + 2 = 444

⇒ 912 - 456 × 28 ÷ 390 + 2 = 444

⇒ 912 - 456 × 0.071 + 2 = 444

⇒ 912 - 32.376 + 2 = 444

⇒ 914 - 32.376 = 444

⇒ 881.624 ≠ 444

3. - आणि 

912 + 456 × 28 - 390 ÷ 2 = 444

⇒ 912 + 456 × 28 - 195 = 444

⇒ 912 + 12768 - 195 = 444

⇒ 13680 - 195 = 444

⇒ 13485 ≠ 444

4. ÷ आणि × 

912 - 456 ÷ 28 + 390 × 2 = 444

⇒ 912 - 456 ÷ 28 + 390 × 2 = 444

⇒ 912 - 16.28 + 780 = 444

⇒ 1692 - 16.28 = 444 
⇒ 1675.72 ≠ 444

म्हणून, '÷ आणि -' हे योग्य उत्तर आहे.

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