Question
Download Solution PDFपाच सलग सम संख्यांची सरासरी 16 आहे, त्या संख्यांचा प्रचरण (वेरीयन्स) शोधा,
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
पाच सलग सम संख्यांची सरासरी = 16
वापरलेले सूत्र:
\({\rm{V}} = \frac{{∑ {{\left| {{\rm{x}} - {\rm{m}}} \right|}^2}}}{{\rm{n}}}\)
\({\rm{Mean\;}}\left( {\rm{m}} \right) = \;\frac{{\left\{ {2{\rm{a\;}} + \left( {{\rm{n\;}} - 1} \right){\rm{d}}} \right\}}}{2}\)
V = प्रचरण (वेरीयन्स)
∑ = समाकलन
x = निरीक्षण
n = निरीक्षणांची संख्या
a = संख्यामधील प्रथम पद
d = सामायिक फरक
गणना:
\(\frac{{\left\{ {2{\rm{a\;}} + \left( {{\rm{n\;}} - 1} \right){\rm{d}}} \right\}}}{2} = 16\)
⇒ 2a + (5 – 1)2 = 32
⇒ 2a + 4 × 2 = 32
⇒ 2a = 32 – 8
⇒ 2a = 24
⇒ a = 12
प्रथम पद = 12
इतर पद आहेत, 14, 16, 18, 20
\({\rm{V}} = {\rm{\;}}\frac{{{{\left( {12{\rm{\;}} - 16} \right)}^2} + {{\left( {14{\rm{\;}} - 16} \right)}^2} + {{\left( {16{\rm{\;}} - 16} \right)}^2} + {{\left( {18{\rm{\;}} - 16} \right)}^2} + {{\left( {20{\rm{\;}} - 16} \right)}^2}}}{5}\)
⇒ \({\rm{\;}}\frac{{16{\rm{\;}} + {\rm{\;}}4{\rm{\;}} + {\rm{\;}}0{\rm{\;}} + {\rm{\;}}4{\rm{\;}} + 16}}{5}\)
⇒ \({\rm{\;}}\frac{{40}}{5}\)
⇒ 8
⇒ V = 8
∴ संख्यांचे प्रचरण (वेरीयन्स) 8 आहे.
Last updated on Jun 27, 2025
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