Question
Download Solution PDFएका शाळेत, 80 गुणांची परीक्षा घेतली गेली, ज्यामध्ये उत्तीर्ण होण्यासाठी 32 गुण आवश्यक होते. तर खालीलपैकी कोणाला सर्वात कमी गुण मिळाले?
सुचना: केवळ एका दशांश स्थानापर्यंत.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
एकूण गुण = 80
उत्तीर्ण गुण = 32
वापरलेले सूत्र:
टक्केवारी = (मिळालेले गुण/एकूण गुण) × 100
एकूण गुणांचा अपूर्णांक = (मिळालेले गुण/एकूण गुण)
गणना:
1) D, ज्याला एकूण गुणांच्या \(\frac{12}{19}\) गुण मिळाले
⇒ मिळालेले गुण = (\(\frac{12}{19}\)) × 80
⇒ मिळालेले गुण = 50.5
2) C, ज्याला उत्तीर्ण गुणांच्या 160% गुण मिळाले
⇒ मिळालेले गुण = (\(\frac{160}{100}\)) × 32
⇒ मिळालेले गुण = 51.2
3) A, ज्याला परीक्षेत 72% गुण मिळाले
⇒ मिळालेले गुण = (\(\frac{72}{100}\)) × 80
⇒ मिळालेले गुण = 57.6
4) B, ज्याला एकूण गुणांच्या \(\frac{7}{11}\) गुण मिळाले
⇒ मिळालेले गुण = (\(\frac{7}{11}\)) × 80
⇒ मिळालेले गुण = 50.9
∴ पर्याय 1 योग्य आहे.
Last updated on Jun 3, 2025
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