एक काटकोन त्रिकोणाचे क्षेत्रफळ काढा ज्याचे पाया 15 सेमी आणि कर्ण 17 सेमी आहे.

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SSC Selection Post 2024 (Matriculation Level) Official Paper (Held On: 26 Jun, 2024 Shift 1)
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  1. 40 सेमी2
  2. 55 सेमी2
  3. 60 सेमी2
  4. 75 सेमी2

Answer (Detailed Solution Below)

Option 3 : 60 सेमी2
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Detailed Solution

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दिलेल्याप्रमाणे:

पाया = 15 सेमी

कर्ण = 17 सेमी

वापरलेले सूत्र:

काटकोन त्रिकोणाचे क्षेत्रफळ = (1/2) x आधार x उंची

पायथागोरस प्रमेय: a2 + b2 = c2

गणना:

उंची काढण्यासाठी पायथागोरस प्रमेय वापरून:

पाया (a) = 15 सेमी

कर्ण (c) = 17 सेमी

उंची (b) = ?

⇒ 152 + b2 = 172

⇒ 225 + b2 = 289

⇒ b2 = 289 - 225

⇒ b2 = 64

⇒ b = 8 सेमी

आता, काटकोन त्रिकोणाचे क्षेत्रफळ काढा:

क्षेत्रफळ = (1/2) x आधार x उंची

⇒ क्षेत्रफळ = (1/2) x 15 सेमी x 8 सेमी

⇒ क्षेत्रफळ = (1/2) x 120 सेमी2

⇒ क्षेत्रफळ = 60 सेमी2

काटकोन त्रिकोणाचे क्षेत्रफळ 60 सेमी2 आहे.

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-> SSC Selection Phase 13 Exam Dates have been announced on 15th July 2025. 

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