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In the star-delta transformation shown in the figure, if P = 150 Ω, Q = 180 Ω and R = 60 Ω, then A = ?

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MPPGCL JE Electrical 28 April 2023 Shift 1 Official Paper
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  1. 260 Ω
  2. 470 Ω
  3. 780 Ω
  4. 312 Ω

Answer (Detailed Solution Below)

Option 3 : 780 Ω
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Detailed Solution

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Star to Delta Conversion

The delta equivalent of a star connected resistor is:

\(R_A={R_PR_Q+R_QR_R+R_RR_P\over R_R}\)

\(R_B={R_PR_Q+R_QR_R+R_RR_P\over R_Q}\)

\(R_C={R_PR_Q+R_QR_R+R_RR_P\over R_P}\)

Calculation

Given, P = 150 Ω, Q = 180 Ω and R = 60 Ω

\(R_A={150\times 180+180\times 60+60\times 150\over 60}\)

\(R_A=780\space {\Omega}\)

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