In the electronic spectrum of [IrBr6]2−, the number of charge transfer band(s) and their origin are, respectively

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CSIR-UGC (NET) Chemical Science: Held on (15 Dec 2019)
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  1. Two, ligand → metal (σ → t2g and σ → a1g*)
  2. One, ligand → metal (σ → eg)
  3. Two, ligand → metal (σ → t2g and σ → eg)
  4. One, ligand → metal (σ → tg)

Answer (Detailed Solution Below)

Option 3 : Two, ligand → metal (σ → t2g and σ → eg)
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Detailed Solution

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Concept:

Charge Transfer complex:

  • charge transfer complex or an electron donor-acceptor complex describes a type of assembly of two or more molecules or ions.
  • Charge transfer complex is of 4 types, these are 
    • Ligand to metal charge transfer (LMCT),
    • Metal to ligand charge transfer (MLCT),
    • Ligand-to-ligand charge transfer (LLCT), and
    • Metal-to-metal charge transfer (MMCT).
  • It is a correlation between the energies of charge transfer absorptions and the electrochemical properties of metals and ligands.
  • Charge transfer transitions are not restricted by the selection rules that involve ‘d–d ’ transitions, The probability of these electronic transitions is very high, and the absorption bands are therefore intense.

​LMCT:

  • The transfer of an electron from an orbital primarily ligand character to one with primarily metal character is known as ligand-to-metal charge transfer or LMCT.
  • LMCT occurs if a ligand that can be easily oxidized is bound to a metal center in a high oxidation state, which is readily reduced.

Explanation:-

  • In [IrBr6]2−, the oxidation state of Ir is +4 and Ir4+ is in low spin state.
  • [IrBr6]2− is an octahedral complex and the electronic configuration, of Ir4+(d5) is t2g5eg0.
  • Given below is a MO diagram for ML6 octahedral complex

F3 Vinanti Teaching 29.05.23 D109

  • The 5 t2g electrons of Ir4+(d5 or  t2g5eg0) will occupy the t2g non-bonding orbitals (HOMO).
  • This will result in two LMCT transitions from 

σ → t2g and σ → eg.

Conclusion:-

  • Hence, Two, ligand → metal (σ → t2g and σ → eg)  is the correct answer.
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