In a series RL circuit the value of inductance is 1 Henry and resistance is 10 ohms. What is the time constant of the circuit?

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VSSC (ISRO) Technician B (Electronic Mechanic) Previous Year Paper (Held on 25 Sept 2016)
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  1. 0.1 sec
  2. 1 sec
  3. 10 sec
  4. None of the above

Answer (Detailed Solution Below)

Option 1 : 0.1 sec
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Detailed Solution

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Concept: 

F1 Tapesh Anil 20.01.21 D14

We can use Kirchhoff’s Voltage Law, (KVL) to define the individual voltage drops that exist around the circuit and then hopefully use it to give us an expression for the flow of current.

\(I_t = \frac{V}{R}\left( {1 - {e^{\frac{{Rt}}{L}}}} \right)\)

The Time Constant, ( τ ) of the LR series circuit is given as L/R and in which V/R represents the final steady-state current value after five-time constant values.

Calculation:

L = 1 H, R = 10Ω

Time constant = 1/10 = 0.1 sec

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