In a pure inductive circuit, if the frequency of the AC source is doubled, then its inductive reactance will:

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  1. become zero
  2. be doubled
  3. remain the same
  4. be halved

Answer (Detailed Solution Below)

Option 2 : be doubled
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Concept

For a pure inductive circuit, the inductive reactance is given by:

\(X_L=2\pi f L\)

where, XL = Inductive reactance

f = Frequency

L = Inductance

Explanation

From the above expression, the inductive reactance is proportional to the frequency.

XL α f

So, if the frequency of the AC source is doubled, then the inductive reactance will also be doubled.

Additional Information For a pure capacitive circuit, the capacitive reactance is given by:

\(X_C={1\over 2\pi f C}\)

\(X_c\space \alpha \space {1\over f}\)

The capacitive reactance is inversely proportional to the frequency.

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