If \({2p \over {p^2 - 5p + 1}} = {1 \over10}, p \ne 0\), then the value of \(({p + \frac{1}{p}})\) is:

Question

Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 08 Dec 2022 Shift 2)

Answer 1

Given:

\({2p \over {p^2 - 5p + 1}} = {1 \over10}, p \ne 0\)

Calculations:

According to question,

\({2p \over {p^2 - 5p + 1}} = {1 \over10}, p \ne 0\),

⇒20p = p² - 5p + 1

⇒p² + 1 = 25p

⇒p + 1/p = 25

Hence, The Required value is 25.

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