If y = 1 + √3 + √4, then the value of 2y4 - 8y3 - 6y2 + 28y - 84 is:

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SSC CGL 2022 Tier-I Official Paper (Held On : 08 Dec 2022 Shift 2)
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  1. 40√3 
  2. 80√3
  3. 20√3
  4. 60√3

Answer (Detailed Solution Below)

Option 1 : 40√3 
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Detailed Solution

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Given:

y = 1 + √3 + √4

Formula used:

(x + y)2 = x2 + y2 +2xy

Calculations:

 y = 1 + √3 + √4,

 y = 1 + √3 + 2 = 3 + √3

 y2 = (3 + √3)2

 y2 = 9 +3 + 6√3 = 12 + 6√3

According to the question,

⇒ 2y4 - 8y3 - 6y2 + 28y - 84

⇒ 2y2(y2 - 4y - 3) + 28(3 + √3) - 84

⇒ 2y2(y2 - 4y - 3 + 4 - 4) + 84 + 28√3 - 84

⇒ 2y2(y2 - 4y + 4 - 7) + 28√3

⇒ 2y2{(y-2)2 - 7} + 28√3

Now put the value of y and y2

⇒ 2(12 + 6√3){(3 + √3 -2)2 - 7} + 28√3

⇒ (24 + 12√3){(1 + √3)2 - 7} + 28√3

⇒ (24 + 12√3){1 + 3 + 2√3 - 7} + 28√3

⇒ (24 + 12√3){2√3 - 3} + 28√3

⇒ 48√3 - 72 + 72 - 36√3 + 28√3

⇒ 40√3

⇒ Hence, Option 1 is correct

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