If α and β are the roots of the equation 2x2 - 3x - 5 = 0, then the quadratic equation whose roots are  and  is:

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RRB Group D 26 Sept 2022 Shift 2 Official Paper
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  1. 10x2 - 29x + 10 = 0
  2. 10x2 + 29x + 10 = 0
  3. 10x2 + 29x - 10 = 0
  4. 10x2 - 29x - 10 = 0

Answer (Detailed Solution Below)

Option 2 : 10x2 + 29x + 10 = 0
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RRB Group D Full Test 1
100 Qs. 100 Marks 90 Mins

Detailed Solution

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Given:

The roots of equation 2x2 - 3x - 5 = 0 are α and β.

The roots of another equation are  and .

Calculation:

Using the hit and trial method on the given equation to find values of α and β.

2x2 - 3x - 5 = 0

= 2x2 - 5x + 2x - 5 

= x(2x - 5) +1(2x - 5)

= (2x - 5)(x + 1)

x =  and x = -1

thus α =  and β = -1

Now solving,  and , we get 

 =  

 = 

Now,

Quadratic equation whose roots are  and :

(x - ()) (x - ()) = 0

⇒ (x + 5/2) (x + 2/5) = 0

⇒ x2 + 5x/2 + 2x/5 + 1 = 0

⇒ (10x2 + 25x + 4x + 10)/10 = 0

⇒ 10x2 + 29x + 10 = 0

∴ The correct answer is option (2)

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