Question
Download Solution PDFदो समरूप त्रिभुज ΔXYZ और ΔLMN हैं। यदि (ΔXYZ) का क्षेत्रफल = 16 सेमी2, (ΔLMN) का क्षेत्रफल = 25 सेमी2 और YZ = 2.4 सेमी है, तो MN की माप है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
ΔXYZ का क्षेत्रफल = 16 सेमी2
ΔLMN का क्षेत्रफल = 25 सेमी2
YZ = 2.4 सेमी
प्रयुक्त सूत्र:
\( \frac{\text{ΔXYZ का क्षेत्रफल}}{\text{ΔLMN का क्षेत्रफल}} = \left( \frac{\text{YZ}}{\text{MN}} \right)^2\)
गणना:
\(\frac{16}{25} = \left( \frac{2.4}{\text{MN}} \right)^2\)
⇒ \(\sqrt{\frac{16}{25}} = \frac{2.4}{\text{MN}}\)
⇒ \( \frac{4}{5} = \frac{2.4}{\text{MN}}\)
⇒ \( \text{MN} = \frac{2.4 \times 5}{4}\)
⇒ MN = 3 सेमी
इसलिए, MN की माप 3 सेमी है।
Last updated on Jun 17, 2025
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