Question
Download Solution PDFअनुप्रयुक्त बल आघूर्ण के कारण शाफ्ट में प्रेरित अपरूपण प्रतिबल का परिमाण निम्न से भिन्न होता है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
सरल मरोड़ समीकरण निम्न रुप से लिखा जा सकता है
\(\frac{T}{J} = \frac{\tau }{r} = \frac{{G\theta }}{L}\;or\;\tau = \frac{{G\theta r}}{L}\)
यह बताता है कि अपरुपण प्रतिबल शाफ्ट के अक्ष से दूरी ‘r’ के रूप में सीधे परिवर्तित होता है और प्रतिबल वितरण निम्नानुसार है
इसलिए शाफ्ट के बाह्य सतह पर अधिकतम अपरुपण बल प्राप्त होता है जब r = R होता है और केन्द्र पर अपरुपण प्रतिबल शून्य होता है।
Last updated on Jul 1, 2025
-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been rescheduled on its official website.
-> JKSSB JE exam will be conducted on 31st August (Civil), and on 24th August 2025 (Electrical).
-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27.
-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering.
-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025.
-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025
-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.
-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.
-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.