Question
Download Solution PDF\(\rm \sqrt{\frac{1+sinA}{1-sinA}} =\) ________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया:
\(\rm \sqrt{\frac{1+sinA}{1-sinA}} \)
प्रयुक्त अवधारणा:
यहाँ संयुग्मन की अवधारणा का उपयोग किया जाता है
गणना:
⇒ \(\rm \sqrt{\frac{1+sinA}{1-sinA}} \)
अब, उपरोक्त समीकरणों को संयुग्मित करें
⇒ \(\rm {\sqrt{\frac{1+sinA}{1-sinA} \times \rm {\frac{1+sinA}{1+sinA}}}}\)
⇒ \(\rm \sqrt{\frac{(1+sinA)^2}{1-sin^2A}}\)
⇒ \(\rm \sqrt{\frac{(1+sinA)^2}{cos^2A}}\)
⇒ \(\rm {\frac{(1+sinA)}{cosA}}\)
⇒ \(\frac{1}{ cos A} +\frac{sin A}{ cosA}\)
⇒ sec A + tan A
⇒ अत:, दिए गए भाग का मान sec A + tan A है।
Last updated on Jul 22, 2025
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