यदि 200 सेमी व्यास वाले सीवर में आंशिक प्रवाह की गहराई, पूर्ण प्रवाह की 1/4 है, तो इसका गीला परिमाप है

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  1. πD
  2. \(\frac{2π}{3}\)D
  3. \(\frac{3π}{2}\)D
  4. \(\frac{π}{3}\)D

Answer (Detailed Solution Below)

Option 4 : \(\frac{π}{3}\)D
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समाधान:

वृत्ताकार सीवर में आंशिक प्रवाह के लिए प्रवाह की गहराई और सीवर के व्यास के बीच संबंध \(\frac{d}{D}=\frac{1}{2}\left ( 1-cos\frac{\alpha }{2} \right ) \)

प्रवाह की दी गई गहराई = पूर्ण प्रवाह का 1/4वां भाग ⇒ d = D/4 ⇒ \(\frac{1}{4}=\frac{1}{2}\left ( 1-cos\frac{\alpha }{2} \right ) \)

\(\alpha = 120\) °

इसलिए गीला परिमाप \(p= \frac{\pi D}{360^{\circ}}\times 120^{\circ} = \frac{\pi\times D}{3}\)


अतिरिक्त जानकारी

\(\frac{{\rm{q}}}{{\rm{Q}}} = \left( {\frac{ \propto }{{360^\circ }} - \frac{{\sin \propto }}{{2{\rm{\pi }}}}} \right){\left( {\frac{{\frac{ \propto }{{360^\circ }} - \frac{{\sin \propto }}{{2{\rm{\pi }}}}}}{{ \propto /{\rm{\;}}360^\circ }}} \right)^{2/3}}\) \({\rm{q}} = \frac{1}{{\rm{n}}} \times {\rm{a\;}}{{\rm{r}}^{2/3}}{\rm{\;}}{{\rm{s}}^{1/2}}{\rm{\;and\;r}} = \frac{{\rm{a}}}{{\rm{p}}}\)

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