Question
Download Solution PDFΔABC ∼ ΔPQR है, (ΔABC) का क्षेत्रफल 16 सेमी2 है और (ΔPQR) का क्षेत्रफल 25 सेमी2 है।यदि BC = 20 सेमी है, तब QR का मान कितना है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त अवधारणा:
दो समरूप त्रिभुजों के क्षेत्रफलों का अनुपात, संगत भुजाओं और माध्यिकाओं के वर्गों के अनुपात के बराबर होता है।
गणना
ΔABC ∼ ΔPQR
∴ (BC/QR)2 = (∆ABC) का क्षेत्रफल / (∆PQR) का क्षेत्रफल
⇒ (20/QR)2 = 16/25
⇒ 20/QR = 4/5
∴ QR = 25 सेमी
सही उत्तर 25 सेमी है।
Last updated on Jul 17, 2025
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