Question
Download Solution PDFनीचे दी गयी आकृति में दर्शाया गया शाफ़्ट 1000 N-m के स्थिर बलाघूर्ण के विरुद्ध 100 rev/min की दर पर घूमता है। तो शाफ़्ट को घुमाने के लिए आवश्यक शक्ति क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
संचारित शक्ति की गणना निम्न द्वारा की जा सकती है:
\(P={2π NT\over 60}\)
जहाँ P = शक्ति (W), N = घूर्णन की गति (RPM), और T = बलाघूर्ण (N-m)
गणना:
दिया गया है:
N = 100 RPM, T = 1000 N-m
\(P={2π NT\over 60}\)
\(P={2\times 3.14\times 100\times 1000\over 60}\)..................(जहाँ π = 3.14)
P = 10466.66 W ≈ 10.47 kW
Last updated on May 30, 2025
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