Question
Download Solution PDFएक गोल छड़ जिसकी लंबाई 4 मीटर और व्यास 64 मिमी है, का उपयोग दोनों सिरों पर टिका हुआ स्ट्रट के रूप में किया जाता है। क्रिपलिंग लोड निर्धारित करें (यंग मापांक = 2 x 105 N/mm2 और π3 = 31 मान लें)।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंप्रत्यय:
दोनों सिरों पर टिका हुआ स्ट्रट के लिए ऑयलर का क्रिपलिंग लोड इस प्रकार दिया गया है:
\( P = \frac{\pi^2 \cdot E \cdot I}{L^2} \)
- \( L = 4 \, \text{m} = 4000 \, \text{mm} \)
- \( d = 64 \, \text{mm} \)
- \( E = 2 \times 10^5 \, \text{N/mm}^2 \)
- \( I = \frac{\pi d^4}{64} \)
मानों को प्रतिस्थापित करने और हल करने पर प्राप्त होता है:
\( P \approx 101601.6 \, \text{N} \)
Last updated on Jul 8, 2025
-> The BHEL Cut Off 2025 has been uploaded on July 8, 2025 at the official website
-> BHEL Engineer Trainee result has been released on July 8.
-> BHEL Engineer Trainee answer key 2025 has been released at the official website.
-> The BHEL Engineer Trainee Admit Card 2025 has been released on the official website.
->The BHEL Engineer Trainee Exam 2025 will be conducted on April 11th, 12th and 13th, 2025
-> BHEL Engineer Trainee 2025 Notification has been released on the official website.
-> A total of 150 Vacancies have been announced for various disciplines of Engineering like Mechanical, Electrical, Civil, etc.
-> Interested and eligible candidates can apply from 1st February 2025 to 28th February 2025.
-> The authorities has also released the BHEL Engineer Trainee Pattern
-> The BHEL Engineer Trainee Selection Process is divided into two stages namely Written Test and Interview.
-> The selected candidates for the Engineer Trainee post will get a salary range between Rs. 60,000 - Rs. 1,80,000.