एक कुंडली में 0.4 mm2 के अनुप्रस्थ-काट क्षेत्रफल वाले 1000 फेरे हैं। प्रति फेरे की औसत लंबाई 40 सेमी है और तार की प्रतिरोधकता 0.02μΩ-m है। कुण्डली का प्रतिरोध _______ है।

This question was previously asked in
SSC JE Electrical 11 Oct 2023 Shift 3 Official Paper-I
View all SSC JE EE Papers >
  1. 40Ω
  2. 20µΩ
  3. 200Ω
  4. 20Ω

Answer (Detailed Solution Below)

Option 4 : 20Ω
Free
Electrical Machine for All AE/JE EE Exams Mock Test
8 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

अवधारणा

किसी तार का प्रतिरोध निम्न द्वारा दिया जाता है:

\(R=ρ{l× N\over A}\)

जहाँ, R = प्रतिरोध

ρ = प्रतिरोधकता

l = प्रति फेरा औसत लंबाई

N = फेरो की संख्या

A = अनुप्रस्थ-काट क्षेत्रफल 

गणना

दिया गया है, ρ = 0.02μΩ-m = 0.02 × 10-6 Ω-m

l = 40 सेमी = 40 × 10-2 मीटर

N = 1000

A = 0.4 mm2 = 0.4 × 10-6 m2

\(R={0.02\times 10^{-6}\times 40\times 10^{2}\times 1000\over 0.4\times 10^{-6}}\)

R = 20 Ω

Latest SSC JE EE Updates

Last updated on Jul 1, 2025

-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.

-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

More Network Elements Questions

Get Free Access Now
Hot Links: teen patti master downloadable content dhani teen patti teen patti real cash teen patti go teen patti all app