Question
Download Solution PDFFind the sum of the digits of the smallest 6-digit number divisible by 18, 24 and 25.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept Used:
To find the smallest 6-digit number divisible by 18, 24, and 25,
we need to find their least common multiple (LCM).
Calculation:
LCM of 18, 24, and 25 = 1800
The smallest 6-digit number is 100000.
The smallest multiple of 1800 greater than or equal to 100000 is 100800.
Sum of the digits of 100800 = 1 + 0 + 0 + 8 + 0 + 0 = 9
Therefore, the sum of the digits of the smallest 6-digit number divisible by 18, 24, and 25 is 9.
Last updated on Jul 8, 2025
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