During a division, Pranjal mistakenly took as the dividend a number that was 10% more than the original dividend. He also mistakenly took as the divisor a number that was 25% more than the original divisor. If the correct quotient of the original division problem was 25 and the remainder was 0, what was the quotient that Pranjal obtained, assuming his calculations had no error?

Question

Question

This question was previously asked in

SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 4)

Answer 1

Given:

New dividend = 110% × original dividend

New divisor = 125% × original divisor

Formula used:

Dividend = divisor × quotient + remainder

Calculation:

Let the original dividend = 100x

Mistakenly increased dividend = 100 × 110% = 110x

Let original divisor = 100y

Mistankenly increased divisor = 100y × 125% = 125y

Dividend = divisor × quotient + remainder

100x = 100y × 25 + 0

x/y = 25/1

Increased dividend = 110x = 110 × 25 = 2750

Increased divisor = 125y = 125 × 1 = 125

Quotient = 2750/125 = 22

∴ The correct answer is 22.

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