cos(30° + θ) - sin(60° - θ) = _______.

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SSC CGL 2022 Tier-I Official Paper (Held On : 07 Dec 2022 Shift 3)
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  1. \(\frac{{\sqrt 3 }}{2}\)
  2. 0
  3. \(\frac{{ 1 }}{2}\)
  4. \(\frac{{1 }}{\sqrt2}\)

Answer (Detailed Solution Below)

Option 2 : 0
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Detailed Solution

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Formula used:

cos (A + B) = cos A cos B - sin A sin B

sin (A - B) = sin A cos B - cos A sin B

Calculations:

cos(30° + θ) - sin(60° - θ) 

cos30° × cosθ - sin θ sin 30° -  (sin60° cos θ - cos60° sinθ)

cos30° × cosθ - sin θ sin 30° - sin60° cos θ + cos60° sinθ

Since,

cos 30° = √3/2, sin 30° = 1/2 and

cos 60° = 1/2, sin 60° = √3/2

⇒ (√3/2) cosθ - (1/2)sinθ - (√3/2)cosθ + (1/2)sinθ

⇒ (√3/2) cosθ - (1/2)sinθ - (√3/2)cosθ + (1/2)sinθ

= 0

Hence, The Required value is 0.

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