Question
Download Solution PDFএকটি রম্বসের এক বাহুর দৈর্ঘ্য 41 সেমি এবং এর ক্ষেত্রফল 720 সেমি2, এর কর্ণগুলোর দৈর্ঘ্যের সমষ্টি কত?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFরম্বসের ক্ষেত্রফল = 1/2 × কর্ণের গুণফল
⇒ 720 = 1/2 × কর্ণের গুণফল
⇒ কর্ণের গুণফল = 1440
(রম্বসের বাহু)2 = (এক কর্ণের অর্ধেক)2 + (অন্য কর্ণের অর্ধেক)2
⇒ (এক কর্ণ)2 + (অন্য কর্ণ)2 = 41 × 41 × 4
(দুটি কর্ণের সমষ্টি)2 = (এক কর্ণ)2 + (অন্য কর্ণ)2 + 2 × কর্ণের গুণফল
⇒ (দুটি কর্ণের সমষ্টি)2 = 6724 + 2880 = 9604
∴ দুটি কর্ণের সমষ্টি = 98 সেমিLast updated on Jun 11, 2025
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