Question
Download Solution PDFAn airplane goes 14 km due east and then 48 km due north. How far is it from its initial position?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Distance covered by airplane in the east = 14 km
Distance covered by airplane in the north = 48 km
Concept used:
By Pythagorean theorem
(Hypotenuse)2 = (perpendicular)2 + (base)2
Calculation:
By Pythagorean theorem
⇒ (Hypotenuse)2 = (perpendicular)2 + (base)2
⇒ (AC)2 = (BC)2 + (AB)2
⇒ AC = √{(48)2 + (14)2}
⇒ AC = √{2304 + 196}
⇒ AC = √2500 = 50 km
∴ The correct answer is 50 km.
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