AB is parallel to CD. A transversal PQ intersects AB and CD at E and F, respectively, and ∠PEB = 56°. G is a point between AB and CD such that ∠BEG = 32° and ∠GFE = 47°. What is the measure of ∠EGF?

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RRB NTPC Graduate Level CBT-I Official Paper (Held On: 05 Jun, 2025 Shift 2)
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  1. 29°
  2. 46°
  3. 41°
  4. 37°

Answer (Detailed Solution Below)

Option 3 : 41°
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Detailed Solution

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Given:

AB is parallel to CD.

Transversal PQ intersects AB and CD at E and F respectively.

∠PEB = 56º

∠BEG = 32º

∠GFE = 47º

Formula used:

In a triangle, the sum of angles is 180º:

∠GEF + ∠GFE + ∠EGF = 180º

Calculation:

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∠BEG = 32º

∠GFE = 47º

⇒ ∠GEF = 180º - (∠BEG + ∠PEB)

⇒ ∠GEF = 180º - (32º + 56º)

⇒ ∠GEF = 180º - 88º

⇒ ∠GEF = 92º

Now, GEF + ∠GFE + ∠EGF = 180º

⇒ 92° + 47° + ∠EGF = 180º

⇒ 139° + ∠EGF = 180º

⇒ ∠EGF = 180° - 139° 

⇒ ∠EGF = 41° 

∴ The corect answer is option (3).

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